Home / Estimation / Approximation
3.3c · Estimation · Sub-skill
Estimating the answer to a calculation before working it out exactly, and using approximation to sanity-check results.
Build it up, step by step
Click each step below to reveal it — work through them in order the first time round.
Approximating a calculation before doing it precisely helps you spot mistakes (e.g. a misplaced decimal point) and gives you a quick sense-check of whether your final exact answer is plausible.
To approximate a calculation, round each number to 1 significant figure (or another convenient value) before calculating. E.g. to approximate 38.7 × 21.4, round to 40 × 20 = 800.
The same idea works for division and multi-step calculations: round each part first. E.g. to approximate $\frac{198\times 5.1}{9.8}$, round to $\frac{200\times 5}{10}=\frac{1000}{10}=100$. This is much faster than the exact calculation and gives a good sanity-check figure.
Once you've calculated an exact answer, compare it to your approximation. If they're wildly different, you've likely made an error (e.g. a misplaced decimal point, or pressed the wrong calculator button) and should recheck your working.
Approximate the value of $\frac{612\times 3.9}{19.8}$, then use a calculator to find the exact answer and compare.
Approximate: $\frac{600\times 4}{20}=\frac{2400}{20}=120$.
Exact (calculator): 612×3.9 = 2386.8; 2386.8÷19.8 ≈ 120.55.
The exact answer (≈120.55) is close to the approximation (120), so it's plausible — no obvious error.
Test yourself
A student calculates $\frac{287\times 4.8}{6.1}$ and gets an answer of 22.59.
(a) Use approximation (rounding each value to 1 significant figure) to check whether this answer is reasonable.
(b) Based on your approximation, explain whether you think the student's answer is correct, and suggest what kind of error might have caused it if it is wrong. [4 marks]
(a) Approximate: $\frac{300\times 5}{6}=\frac{1500}{6}=250$.
(b) The approximation (250) is very different from the student's answer (22.59) — roughly 10 times smaller — so the student's answer is not reasonable. A likely cause is a decimal point error, e.g. the student may have divided by 61 instead of 6.1, or made a similar factor-of-10 slip.
Practice
Five short questions on approximation. Work through them, then reveal the mark scheme to check.