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3.6 · Paper 2A · Statistical Techniques
Sampling distributions, confidence intervals and estimating population values from samples.
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The mean of a random sample is called a point estimate for the mean of the whole population. A point estimate from a larger sample is generally more reliable than one from a small sample, since it's less affected by chance variation between individual items — it's not sensible to draw firm conclusions from a sample of size 1.
If you repeatedly take random samples from a population and calculate the mean of each, those sample means themselves form a distribution — one that clusters more tightly around the true population mean than individual values do. For samples of size $n$ from $N(\mu, \sigma^2)$, the sample mean $\bar{X}$ has distribution: $$\bar{X} \sim N\left(\mu, \frac{\sigma^2}{n}\right)$$ The standard deviation of this distribution, $\dfrac{\sigma}{\sqrt{n}}$, is called the standard error of the mean — notice that it shrinks as the sample size $n$ grows.
A point estimate alone doesn't say how reliable it is. A confidence interval gives a range of plausible values together with a stated level of confidence: $$\bar{x} \pm z \times \frac{\sigma}{\sqrt{n}}$$ The most common values of $z$: 90% confidence uses $z=1.64$, 95% uses $z=1.96$, and 99% uses $z=2.58$. A higher confidence level always gives a wider interval, and a larger sample size always gives a narrower one.
A random sample of 25 boxes of cereal, assumed normally distributed with standard deviation 6 g, has a sample mean weight of 502 g.
Find a 95% confidence interval for the true mean weight of a box of cereal.
Standard error $= \dfrac{6}{\sqrt{25}} = 1.2$
95% CI: $502 \pm 1.96 \times 1.2 = 502 \pm 2.352$, giving the interval $(499.6, 504.4)$ to 1 d.p.
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